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0=x^2+7x-11
We move all terms to the left:
0-(x^2+7x-11)=0
We add all the numbers together, and all the variables
-(x^2+7x-11)=0
We get rid of parentheses
-x^2-7x+11=0
We add all the numbers together, and all the variables
-1x^2-7x+11=0
a = -1; b = -7; c = +11;
Δ = b2-4ac
Δ = -72-4·(-1)·11
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{93}}{2*-1}=\frac{7-\sqrt{93}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{93}}{2*-1}=\frac{7+\sqrt{93}}{-2} $
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